Asked in ETEA MDCAT 2015 2015Moderate

An Incompressible liquid flow along the pipe with area of cross section A1 and A2 with velocities V1 and V2 respectively. The ratio of the speeds V1 / V2 is:

Correct answer: B. A2/A1

  • A. A1/A2
  • B. A2/A1
  • C. (A1 + A2)/(V1 + V2)
  • D. (V1 + V2)/(A1 + A2)

Explanation

According to the continuity equation for incompressible fluids, the flow rate (product of cross-sectional area and velocity) is constant. This means that A1V1 = A2V2. From this relationship, we can derive that V1/V2 = A2/A1, making Option B the correct choice.Options A and C incorrectly suggest relationships that don't comply with the continuity equation, while Option D presents a ratio that doesn't apply to the problem's context.

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About Equation of Continuity

The equation of continuity expresses conservation of mass in fluid flow. For steady incompressible flow, Av remains constant, so fluid speed increases when the cross-sectional area decreases; for compressible flow, ρAv is constant. This relation describes flow rate and area-speed changes without including pressure effects from Bernoulli’s equation.

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