A solution A of concentration 0.10 mol dm-3 undergoes first order reaction at an initial rate of 5.0 x 10^-4 mol dm-3 s-1. The value of rate constant for this reaction is:

Correct answer: D. 5 x 10^-3 s-1

  • A. 2 x 10^-3 s-1
  • B. 3 x 10^-3 s-1
  • C. 4 x 10^-3 s-1
  • D. 5 x 10^-3 s-1

Explanation

Option D is correct.The rate constant for a first-order reaction is the proportionality constant between the rate of reaction and the concentration of the reactants. It is a measure of how fast the reaction proceeds. The rate of reaction for a first-order reaction is given by the following equation: rate = k[A] where k is the rate constant and [A] is the concentration of the reactant. In this problem, the initial concentration of the reactant is 0.10 mol dm-3 and the initial rate of reaction is 5.0 x 10-4 mol dm-3 s-1. Substituting these values into the equation for the rate of reaction, we get: 5.0 x 10-4 mol dm-3 s-1 = k(0.10 mol dm-3) .Solving for k, we get: k = 5.0 x 10-4 mol dm-3 s-1 / 0.10 mol dm-3 k= 5 x 10-3 s-1 .Therefore, the value of the rate constant for this reaction is 5 x 10-3 s-1.

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Reaction kinetics relates reaction rate to concentration, temperature, surface area and catalysts. Questions cover rate laws, reaction order, rate constants, activation energy and the activated complex, including how a catalyst lowers the activation energy without changing the overall energy change or equilibrium position.

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