A solid cylinder of mass 20 kg rotates about its axis with angular velocity 10ms-1 radius 0.2m. The moment of inertia of the cylinder is:
Correct answer: B. 0.4 kg m2
- A. 0.2 kg m2
- B. 0.4 kg m2
- C. 0.6 kg m2
- D. 0.8 kg m2
Explanation
To calculate the moment of inertia (I) of a solid cylinder rotating about its axis, we use the formula: I = (1/2) × m × r2 Where: m = mass of the cylinder (20 kg) r = radius of the cylinder (0.2 m) I = (1/2) × 20 kg × (0.2 m)2 I = (1/2) × 20 kg × 0.04 m² I = 0.4 kg m² So, the moment of inertia of the solid cylinder is 0.4 kg m², which matches option (b).
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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