A simple pendulum 4 m long strings with an amplitude of 0.2 m. What is its acceleration at the ends of its path? (g= 10 m/s2 )
Correct answer: C. 0.5 m/s2
- A. zero
- B. 10 m/s2
- C. 0.5 m/s2
- D. 2.5 m/s2
Explanation
The acceleration of a simple pendulum at the ends of its path can be calculated using the formula: a = g * sin(θ), where g is the acceleration due to gravity and θ is the angle of displacement. At maximum amplitude, the angle is such that sin(θ) can be approximated for small angles. Given the parameters, the maximum acceleration is calculated to be 0.5 m/s2 at the extremes of its path.Option A is incorrect because the acceleration is not zero; it reaches maximum at the endpoints. Option B represents the gravitational acceleration, which is not the same as the pendulum's acceleration at maximum displacement. Option D is also incorrect because it overestimates the acceleration based on the given length and amplitude.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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