A particle of mass m is executing uniform circular motion on a path of radius r. If P is the magnitude of its linear momentum. The radial force acting on the particle is
Correct answer: C. p2/rm
- A. mp2/r
- B. rm/p
- C. p2/rm
- D. pmr
Explanation
Option C is correct.The radial force is the centripetal force that keeps the particle moving in a circular path. The centripetal force is given by the following formula: F_c = mv^2/r where: F_c is the centripetal force (N) .m is the mass of the particle (kg) .v is the speed of the particle (m/s). r is the radius of the circle (m) .We can write the magnitude of the linear momentum as: P = mv Substituting this into the equation for the centripetal force, we get: F_c = P^2/mr Therefore, the radial force acting on the particle is P^2/mr.
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About Linear Momentum
Linear momentum is the vector product of mass and velocity, p = mv, and changes when a net external force acts. Work includes impulse as the change in momentum, conservation of momentum in isolated systems, collisions and explosions, and the distinction between elastic, inelastic and perfectly inelastic collisions.
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