A particle executes SHM (amplitude = A) between x = - A and x = + A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then:
Correct answer: A. T1 < T2
- A. T1 < T2
- B. T1 > T2
- C. T1 = T2
- D. T1 = 2T2
Explanation
In S.H.M., the velocity of the particle also oscillates simple harmonically. The speed is greater near the mean position and lesser near the extreme position. Therefore, the time taken for the particle to go from O to A/2 will be less than the time taken to go from A/2 to A. Hence, T1<T2. The mathematical solution is given as:
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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